document.write( "Question 548071: how to solve: ln(x+5)=ln(x-1)-ln(x+1) \n" ); document.write( "

Algebra.Com's Answer #356741 by lwsshak3(11628) $\"\"$ $\"About$

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how to solve: ln(x+5)=ln(x-1)-ln(x+1)
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\n" ); document.write( "ln(x+5)=ln(x-1)-ln(x+1)
\n" ); document.write( "ln(x+5)-ln(x-1)+ln(x+1)=0
\n" ); document.write( "place under single log
\n" ); document.write( "ln[(x+5)(x+1)/(x-1)]=0
\n" ); document.write( "convert to exponential form: base(e) raised to log of number(0)=number[(x+5)(x+1)/(x-1)]
\n" ); document.write( "e^0=(x+5)(x+1)/(x-1)=1
\n" ); document.write( "(x+5)(x+1)=(x-1)
\n" ); document.write( "x^2+6x+5=x-1
\n" ); document.write( "x^2+5x+6=0
\n" ); document.write( "(x+3)(x+2)=0
\n" ); document.write( "x=-3 (reject, (x+1)>0)
\n" ); document.write( "or
\n" ); document.write( "x=-2 (reject, (x+1)>0)
\n" ); document.write( "ans: no solution \n" ); document.write( "

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