document.write( "Question 548139: the perimeter of a rectangle is 128. the length is 1 m more than twice the width. find the dimension, what is the length and the width \n" ); document.write( "
Algebra.Com's Answer #356731 by Maths68(1474)\"\" \"About 
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the perimeter of a rectangle is 128. the length is 1 m more than twice the width. find the dimension, what is the length and the width\r
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\n" ); document.write( "\n" ); document.write( "Length = l=2w+1 m
\n" ); document.write( "Width = w
\n" ); document.write( "Perimeter = p = 128 m \r
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\n" ); document.write( "\n" ); document.write( "Perimeter of a Rectangle = length + length + width + width
\n" ); document.write( "Perimeter of a Rectangle =2 length +2 width
\n" ); document.write( "p = 2l +2w
\n" ); document.write( "Put the value of l and p in above equation
\n" ); document.write( "128 = 2(2w+1)+2w
\n" ); document.write( "128 = 4w+2+2w
\n" ); document.write( "128-2=6w
\n" ); document.write( "126=6w
\n" ); document.write( "Divide by 6 both sides of above equation
\n" ); document.write( "126/6=6w/6
\n" ); document.write( "21=w
\n" ); document.write( "w=21
\n" ); document.write( "Given
\n" ); document.write( "Length = l=2w+1=2(21)+1=42+1=43m\r
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\n" ); document.write( "\n" ); document.write( "Dimension of rectangle
\n" ); document.write( "p=128
\n" ); document.write( "length=43
\n" ); document.write( "Width=21\r
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