document.write( "Question 548135: two consecutive odd numbers are such that three times the first is 5 more than twice the second. What are those two odd numbers?
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Algebra.Com's Answer #356724 by Maths68(1474)\"\" \"About 
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\n" ); document.write( "Let x+1 is first odd integer
\n" ); document.write( "and x+3 is Second odd integer
\n" ); document.write( "3 times of the first integer = 3(x+1)
\n" ); document.write( "Twice the second integer=2(x+3)\r
\n" ); document.write( "\n" ); document.write( "Condition says
\n" ); document.write( "three times the first is 5 more than twice the second
\n" ); document.write( "3(x+1)=2(x+3)+5
\n" ); document.write( "3x+3=2x+6+5
\n" ); document.write( "3x-2x=6+5-3
\n" ); document.write( "x=8\r
\n" ); document.write( "\n" ); document.write( "First odd integer = x+1=8+1=9
\n" ); document.write( "Second odd integer = x+3=8+3=11\r
\n" ); document.write( "\n" ); document.write( "Check
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\n" ); document.write( "\n" ); document.write( "three times the first is 5 more than twice the second
\n" ); document.write( "3*9=2*11+5
\n" ); document.write( "27=22+5
\n" ); document.write( "27=27
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