document.write( "Question 548035: Can you please help me solve this problem?
\n" ); document.write( "\"A chemist mixed a 20% alcohol solution with a 12% alcohol solution to obtain 200mL of a 15% alcohol solution. How many mL of the 20% solution did he use?\"
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Algebra.Com's Answer #356711 by ankor@dixie-net.com(22740)\"\" \"About 
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A chemist mixed a 20% alcohol solution with a 12% alcohol solution to obtain 200mL of a 15% alcohol solution.
\n" ); document.write( "How many mL of the 20% solution did he use?\"
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\n" ); document.write( "Let x = amt of 20% solutions required
\n" ); document.write( "It states the results should be 200 ml, therefore
\n" ); document.write( "(200-x) = amt of 12% required
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\n" ); document.write( "Write a decimal equiv mixture equation
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\n" ); document.write( ".20x + .12(200-x) = .15(200)
\n" ); document.write( ".20x + 24 - .12x = 30
\n" ); document.write( ".20x - .12x = 30 - 24
\n" ); document.write( ".08x = 6
\n" ); document.write( "x = \"6%2F.08\"
\n" ); document.write( "x = 75 ml of 20% solution
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\n" ); document.write( "Check this (200-75=125 ml of 12%)
\n" ); document.write( ".20(75) + .12(125) = .15(200)
\n" ); document.write( "15 + 15 = 30; confirms our solution
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