document.write( "Question 548052: Log.base(2) (2x-3)= log.base(2) (x-4)\r
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\n" ); document.write( "\n" ); document.write( "I can't solve for x. I keep trying but It's Not working. If it's possible to see the steps I would appreciate it.
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Algebra.Com's Answer #356683 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
Log.base(2) (2x-3)= log.base(2) (x-4)
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\n" ); document.write( "\"log%282%2C%282x-3%29%29+=+log%282%2C%28x-4%29%29\"
\n" ); document.write( "2x-3 = x-4 since their logs are equal
\n" ); document.write( "x = -1
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\n" ); document.write( "--> log(-5) = log(-5) but there are no logs of negative numbers
\n" ); document.write( "--> no solution\r
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