document.write( "Question 547972: Hey, Im stuck on this one question for HOMEWORK, so I would like if this would be answered ASAP.
\n" ); document.write( "the question is: The length of a rectangle is ten less than three times its width. If the width is increased by five and
\n" ); document.write( "the length is increased by two, then the perimeter of the new rectangle is 90cm. Find the dimensions of
\n" ); document.write( "the original rectangle.
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Algebra.Com's Answer #356667 by nerdybill(7384)\"\" \"About 
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The length of a rectangle is ten less than three times its width. If the width is increased by five and the length is increased by two, then the perimeter of the new rectangle is 90cm. Find the dimensions of the original rectangle.
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\n" ); document.write( "Let x = width
\n" ); document.write( "then
\n" ); document.write( "3x-10 = length
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\n" ); document.write( "width increased by 5:
\n" ); document.write( "x+5
\n" ); document.write( "length increased by 2:
\n" ); document.write( "3x-10+2 = 3x-8
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\n" ); document.write( "2(x+5 + 3x-8) = 90
\n" ); document.write( "2(4x+5-8) = 90
\n" ); document.write( "2(4x-3) = 90
\n" ); document.write( "4x-3 = 45
\n" ); document.write( "4x = 48
\n" ); document.write( "x = 14 cm (width)
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\n" ); document.write( "Length:
\n" ); document.write( "3x-10 = 3(14)-10 = 42-10 = 32 cm
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\n" ); document.write( "Dimensions:
\n" ); document.write( "14 cm by 32 cm\r
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