document.write( "Question 545805: cos(arcsin(-3/5)) \n" ); document.write( "
Algebra.Com's Answer #356638 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! cos(arcsin(-3/5)) \n" ); document.write( "arcsin(-3/5) is a reference angle whose sin=-3/5 in quadrant IV where sin<0 and cos>0. \n" ); document.write( "note: arcsin(-3/5) could also be in quadrant III where sin is also<0, but its domain is: [-π/2, π/2] \n" ); document.write( ".. \n" ); document.write( "cos of this same reference angle=4/5 \n" ); document.write( "Therefore, cos(arcsin(-3/5))=4/5 \n" ); document.write( " |