document.write( "Question 547829: the departure times for two buses are shown below. (Bus a: departs at 9:00 A.M) and Bus b departs at 9:15 A.M.) Bus A travels at a rate of 20 miles per hour, and bus B travels at a rate of 24 miles per hour. At what time will theb uses hve traveled the same distance? \n" ); document.write( "

Algebra.Com's Answer #356587 by josmiceli(19441) $\"\"$ $\"About$

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\n" ); document.write( "\" At what time will the busses meet? \"
\n" ); document.write( "The key is:
\n" ); document.write( "\" How much of a head start over B does A have?
\n" ); document.write( "In 15 min, bus A goes
\n" ); document.write( " $\"+d%5B1%5D+=+20%2A%2815%2F60%29+\"$ mi
\n" ); document.write( " $\"+d%5B1%5D+=+5+\"$ mi
\n" ); document.write( "----------------
\n" ); document.write( "Start a stopwatch when bus B leaves
\n" ); document.write( "and call the time when they meet $\"t\"$
\n" ); document.write( "Let $\"d\"$ = distance B will now travel
\n" ); document.write( "equation for bus A:
\n" ); document.write( "(1) $\"+d+-+5+=+20t+\"$
\n" ); document.write( "equation for bus B:
\n" ); document.write( "(2) $\"+d+=+24t+\"$
\n" ); document.write( "substitute (2) into (1)
\n" ); document.write( "(1) $\"+24t+-+5+=+20t+\"$
\n" ); document.write( "(1) $\"+4t+=+5+\"$
\n" ); document.write( "(1) $\"+t=+5%2F4+\"$ hrs
\n" ); document.write( "They will have traveled the same distance
\n" ); document.write( "in 1 hr and 15 min, which will be
\n" ); document.write( "9:15 + 1.25 = 10:30
\n" ); document.write( "check answer:
\n" ); document.write( "(2) $\"+d+=+24%2A1.25+\"$
\n" ); document.write( "(2) $\"+d+=+30+\"$
\n" ); document.write( "and
\n" ); document.write( "(1) $\"+d+-+5+=+20%2A1.25+\"$
\n" ); document.write( "(1) $\"+d+-+5+=+25+\"$
\n" ); document.write( "(1) $\"+d+=+30+\"$
\n" ); document.write( "OK \n" ); document.write( "

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