document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=547733>Question 547733</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many gallons of 80% antifreeze should be mixed with 15 gallons of 40% antifreeze to obtain a 55% antifreeze mixture? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #356546 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=356546\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 	--------percent	----------------	quantity									<BR>\n" );
document.write( "Antifreeze I	40	----------------			15	gallons						<BR>\n" );
document.write( "Antifreeze II	80	----------------			x	gallons						<BR>\n" );
document.write( "Mixture	55	----------------	15	+	x	gallons						<BR>\n" );
document.write( "												<BR>\n" );
document.write( "40*15+80x=55(15+x)<BR>\n" );
document.write( "600+80x=25+55x				<BR>\n" );
document.write( "80x+-55	x=	825	-	-600				<BR>\n" );
document.write( "25x=225									<BR>\n" );
document.write( "/	25											<BR>\n" );
document.write( "x	=	9										<BR>\n" );
document.write( "		9	gallons		of			Antifreeze II				<BR>\n" );
document.write( "												<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );