document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=547749>Question 547749</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi, I was wondering if someone could help me with this problem. I am told to expressthe logarithm of a single quantity and the problem is logba+logbc. I am not sure how to solve this. Thank you so much in advance for any help you can give me.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #356544 by </B><A HREF=/tutors/aboutme.mpl?userid=mathie123><B>mathie123(224)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mathie123><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=356544\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> We have a log rule that says \r<BR>\n" );
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document.write( "log(a)+log(b)=log(ab)\r<BR>\n" );
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document.write( "((AS LONG AS THE BASE OF BOTH LOGS ARE THE SAME)) \r<BR>\n" );
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document.write( "So for your question we are just using this rule <BR>\n" );
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