document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=547728>Question 547728</A>: <I><SPAN STYLE=\"word-break: break-all;\"> graph the function - label vertex and axis of symmetry<BR>\n" );
document.write( "y=-(x+3)^2 + 5\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #356537 by </B><A HREF=/tutors/aboutme.mpl?userid=mathie123><B>mathie123(224)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mathie123><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=356537\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> So for any parabola, we have the following possible transformations:\r<BR>\n" );
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document.write( "where (h,k) is the vertex, and a is the dilation and reflection.  \r<BR>\n" );
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document.write( "So from this we can see that  (-3,5) is the vertex, and we are reflecting it along the x axis (since a=-1).\r<BR>\n" );
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document.write( "So we have y=x^2(the base function) to begin\r<BR>\n" );
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document.write( "And now we reflect it along the x axis <BR>\n" );
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document.write( "And we use the vertex point (or slide the whole thing to the left 3 units and up 5 units<BR>\n" );
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document.write( "We can also make a table of values and check if they match with our graph.  <BR>\n" );
document.write( "Hopefully this helps! </SPAN>\n" );
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