document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=547690>Question 547690</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the ending balance in an account that opens with $6,000 earns 4.5% interest compunded quartley and is held for 20 years round your answer to neaest cent. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #356513 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=356513\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Principal P =	6000									<BR>\n" );
document.write( "Amount=	A									<BR>\n" );
document.write( "years=n	20.00									<BR>\n" );
document.write( "compounded	4	times a year		t						<BR>\n" );
document.write( "Rate =	4.50			0.01						<BR>\n" );
document.write( "Amount =	P*((n+r)/n)^n*t									<BR>\n" );
document.write( "										<BR>\n" );
document.write( "Amount =6000*(1+0.01)^20*4<BR>\n" );
document.write( "Amount = 6000*(1+0.01)^	80			<BR>\n" );
document.write( "	6000*(1.01)^80					<BR>\n" );
document.write( "Amount =	14683.65									<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );