document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=547715>Question 547715</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Which of the following can be the average (arithmetic mean) of four consecutive positive even integers? <BR>\n" );
document.write( "A) 2<BR>\n" );
document.write( "B) 3<BR>\n" );
document.write( "C) 4<BR>\n" );
document.write( "D) 5<BR>\n" );
document.write( "E) 6 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #356510 by </B><A HREF=/tutors/aboutme.mpl?userid=htmentor><B>htmentor(1343)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=htmentor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=htmentor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=356510\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let n = the first integer<BR>\n" );
document.write( "Then the 4 consecutive positive integers are: n, n+2, n+4, n+6<BR>\n" );
document.write( "Average = a = (n + n+2 + n+4 + n+6)/4<BR>\n" );
document.write( "Collect terms:<BR>\n" );
document.write( "4a = 4n + 12<BR>\n" );
document.write( "a = n + 3 -> a - n = 3<BR>\n" );
document.write( "Since n is even, the average, a, must be odd<BR>\n" );
document.write( "The two possible choices are B) and D)<BR>\n" );
document.write( "If a = 3, that means n = 0.  But since 0 is not a positive integer, the answer is D). </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );