document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=547673>Question 547673</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the dimensions of a rectangle whose perimeter is 26 meters and whose area is 40 square meters. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #356487 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=356487\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Area = 40<BR>\n" );
document.write( "perimeter =26\r<BR>\n" );
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document.write( "L*W=40<BR>\n" );
document.write( "L=40/w\r<BR>\n" );
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document.write( "Perimeter = 2(L+W)=26\r<BR>\n" );
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document.write( "substitute L \r<BR>\n" );
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document.write( "2(40/w  + w)=26<BR>\n" );
document.write( "2(40+w^2)/W=26<BR>\n" );
document.write( "40+W^2=26*w/2<BR>\n" );
document.write( "W^2+40=13W<BR>\n" );
document.write( "W^2-13W+40=0<BR>\n" );
document.write( "W^2-8W-5W+40=0<BR>\n" );
document.write( "W(W-8)-5(W-8)=0<BR>\n" );
document.write( "(W-8)(W+5)=0<BR>\n" );
document.write( "so W=8m the positive value\r<BR>\n" );
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document.write( "length = 5 m </SPAN>\n" );
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