document.write( "Question 547665: Area of a rectangular window is to be 306 square centimeters. If the length exceeds the width by 1 cm, what are the dimensions? \n" ); document.write( "
Algebra.Com's Answer #356474 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Width of window = 1 x cm \n" ); document.write( "length of window = x+ 1 cm \n" ); document.write( "Area of retangle = Length * width \n" ); document.write( "Area = 306 Cm^2 \n" ); document.write( " \n" ); document.write( "x(x+ 1 ) = 306 \n" ); document.write( " \n" ); document.write( "X^2 + 1 x * 1 + 1 ) \n" ); document.write( " \n" ); document.write( "X^2 + 1 x -305 = 0\r \n" ); document.write( "\n" ); document.write( "x^2+18x-17x-305=0 \n" ); document.write( "x(x+18)-17(x+18)=0 \n" ); document.write( "(x-17)(x+18)=0 \n" ); document.write( "x=17 which is positive \n" ); document.write( "the dimensions are 17 & 18 \n" ); document.write( " \n" ); document.write( " |