document.write( "Question 547525: Solve the system using elimination or substitution method.\r
\n" ); document.write( "\n" ); document.write( "1/4x +1/5y = 3/5
\n" ); document.write( "3x-6y=24
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Algebra.Com's Answer #356414 by mananth(16946)\"\" \"About 
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(1/4)x +(1/5)y = 3/5\r
\n" ); document.write( "\n" ); document.write( "LCD = 20
\n" ); document.write( "multiply by LCD
\n" ); document.write( "1*20/4x +1*20/5y = 3*20/5
\n" ); document.write( "5x+4y=12
\n" ); document.write( "3x-6y=24\r
\n" ); document.write( "\n" ); document.write( "5 x + 4 y = 12 .............1
\n" ); document.write( "-6 y = 24 -3 x ---------2
\n" ); document.write( "/ -6 =
\n" ); document.write( " y = -4 + 0.5 x
\n" ); document.write( "Substitute y in (1)
\n" ); document.write( "5 x + 4 ( -4 + 0.5 x
\n" ); document.write( "5 x -16 + 2 x = 12
\n" ); document.write( "5 x + 2 x = 12 16
\n" ); document.write( "7 x = 28
\n" ); document.write( "/ 7
\n" ); document.write( "x= 4
\n" ); document.write( "Plug the value of x in (1)
\n" ); document.write( "5 x + 4 y = 12
\n" ); document.write( "5 * 4 + 4 y = 12
\n" ); document.write( "20 + 4 y = 12
\n" ); document.write( "4 y = -8
\n" ); document.write( "/ 4
\n" ); document.write( "y= -2
\n" ); document.write( "m.ananth@hotmail.ca \r
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