document.write( "Question 53186: One solution contains 10% alcohol while another contains 30% alcohol. How many liters of each should be mixed to give 10 L of a solution which is 25% alcohol? \n" ); document.write( "
Algebra.Com's Answer #35641 by ankor@dixie-net.com(22740)\"\" \"About 
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One solution contains 10% alcohol while another contains 30% alcohol. How many liters of each should be mixed to give 10 L of a solution which is 25% alcohol?
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\n" ); document.write( "We know that the two mixture amts add up to 10L;
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\n" ); document.write( "Let x = 10% amt; then (10-x) = 30% amt
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\n" ); document.write( "Write a percent equation:
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\n" ); document.write( ".10x + .30(10-x) = .25(10)
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\n" ); document.write( ".10x + 3.0 - .3x = 2.5
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\n" ); document.write( " .1x - .3x = 2.5 - 3.0
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\n" ); document.write( " -.2x = -.5
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\n" ); document.write( " x = -.5/-.2
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\n" ); document.write( " x = + 2.5 liters of 10% mixture
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\n" ); document.write( "10 - 2.5 = 7.5 liters of the 30% mixture
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\n" ); document.write( "Check our solutions:
\n" ); document.write( ".10(2.5) + .30(7.5) = .25(10)
\n" ); document.write( " .25 + 2.25 = 2.5
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