document.write( "Question 6571: Can someone help with question:
\n" ); document.write( "Graph the parabola:
\n" ); document.write( "y=(x-3)^2-3 \n" ); document.write( "
Algebra.Com's Answer #3564 by longjonsilver(2297)\"\" \"About 
You can put this solution on YOUR website!
right then, \"y=%28x-3%29%5E2-3\" is a u-shaped curve.\r
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\n" ); document.write( "\n" ); document.write( "When x=0, \"y=%28-3%29%5E2+-+3\" --> y=9-3 --> y=6\r
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\n" ); document.write( "\n" ); document.write( "When y=0, \"%28x-3%29%5E2+-+3+=+0\"\r
\n" ); document.write( "\n" ); document.write( "\"%28x-3%29%5E2+=+3\"
\n" ); document.write( "x-3 = +- \"sqrt%283%29\"\r
\n" ); document.write( "\n" ); document.write( "so either x = \"3%2Bsqrt%283%29\"
\n" ); document.write( "or x = \"3-sqrt%283%29\"\r
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\n" ); document.write( "\n" ); document.write( "this gives you enough info to sketch the curve.\r
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\n" ); document.write( "\n" ); document.write( "If you want to PLOT it properly, then pick various x values and find the y-values then plot them.\r
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\n" ); document.write( "\n" ); document.write( "jon.
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