document.write( "Question 547345: 24x^2y-12x^2+20xy-10x is the polynomial I am supposed to factor out. \r
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document.write( "I factor with 2x the first time around, I am then left with 2x[3x(4y-2)5(2y-1)] in which I do not have \"twin parenthesis, what am I doing wrong here? \n" );
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Algebra.Com's Answer #356348 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! 24x^2y-12x^2+20xy-10x \n" ); document.write( "----------------- \n" ); document.write( "2x(12xy -6x +10y - 5) \n" ); document.write( "------ \n" ); document.write( "2x[6x(2y-1)+5(2y-1)] \n" ); document.write( "----- \n" ); document.write( "2x(2y-1)(6x+5) \n" ); document.write( "======= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "================= \n" ); document.write( " |