document.write( "Question 547289: The length of a room is 4 less than twice its width. What are the dimensions of the room if the perimeter is 58 feet? \n" ); document.write( "

Algebra.Com's Answer #356330 by mathie123(224) $\"\"$ $\"About$

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Let l be the length of the room and w be the width of the room.
\n" ); document.write( "From the question we can get two equations :
\n" ); document.write( " $\"2w-4=l\"$ (1)
\n" ); document.write( "and
\n" ); document.write( " $\"2w%2B2l=58+\"$ (2) (this is the formula for perimeter of a rectangle)\r
\n" ); document.write( "\n" ); document.write( "Substituing (1) into (2) we get:
\n" ); document.write( " $\"2w%2B2%282w-4%29=58\"$
\n" ); document.write( " $\"2w%2B4w-8=58\"$
\n" ); document.write( " $\"6w-8=58\"$
\n" ); document.write( " $\"6w-8%2B8=58%2B8\"$
\n" ); document.write( " $\"6w=66\"$
\n" ); document.write( " $\"6w%2F6=66%2F6\"$
\n" ); document.write( " $\"w=11\"$ \r
\n" ); document.write( "\n" ); document.write( "Now substituting this value for w into (1) we get:
\n" ); document.write( " $\"2%2A11-4=l\"$
\n" ); document.write( " $\"22-4=l\"$
\n" ); document.write( " $\"l=18\"$ \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Therefore the room is 18 by 11. \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Hopefully this helps, let me know if you still are not sure. \r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

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