document.write( "Question 53161: A NUMBER IS 21/10 MORE THAN ITS RECIPROCAL. FIND THE NUMBER.
\n" ); document.write( "DOMAIN (2/5, 3/5, 5/4, 5/2) \n" ); document.write( "
Algebra.Com's Answer #35633 by ankor@dixie-net.com(22740)\"\" \"About 
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A NUMBER IS 21/10 MORE THAN ITS RECIPROCAL. FIND THE NUMBER.
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\n" ); document.write( "21/10 can easily be handled as decimal; 2.1, so we can write it:
\n" ); document.write( "x = 1/x + 2.1
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\n" ); document.write( "Mult equation by x to get rid of the denominator, you have:
\n" ); document.write( "x^2 = 1 + 2.1x
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\n" ); document.write( "x^2 - 2.1x - 1 = 0 arranged as a quadratic equation
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\n" ); document.write( "Solve for x your favorite method and you get
\n" ); document.write( "x = +2.5, x = -.4
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\n" ); document.write( "if you prefer fractions:
\n" ); document.write( "x = 5/2, x = -4/10
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\n" ); document.write( "Check with x = 2.5
\n" ); document.write( "2.5 = (1/2.5) + 2.1
\n" ); document.write( "2.5 = .5 + 2.1
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\n" ); document.write( "Check with x = -.4
\n" ); document.write( "-.4 = (1/-.4) + 2.1
\n" ); document.write( "-.4 = -2.5 + 2.1\r
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