document.write( "Question 547282: \"f%28x%29=+%283x%5E2-6%29%2F%28x%5E2-4x%29\"\r
\n" ); document.write( "\n" ); document.write( "\"h%28x%29=+6x%2B2\"\r
\n" ); document.write( "\n" ); document.write( "find the domain of f(h(x))\r
\n" ); document.write( "\n" ); document.write( "I have no clue thanks bunches for help
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #356324 by mathie123(224)\"\" \"About 
You can put this solution on YOUR website!
To find f(h(x)), we need to plug in h(x) for any x we see in f(x). This leaves:\r
\n" ); document.write( "\n" ); document.write( "\"f%28x%29=+%283%286x%2B2%29%5E2-6%29%2F%28%286x%2B2%29%5E2-4%286x%2B2%29%29\"
\n" ); document.write( "We could expand this... though it is not needed and will take some time. Instead, we know that there is no limitations on x in the numerator. But we do know that when there is a fraction, the denominator cannot be equal to 0.
\n" ); document.write( "This means that
\n" ); document.write( "\"%286x%2B2%29%5E2-4%286x%2B2%29\" cannot equal 0. \r
\n" ); document.write( "\n" ); document.write( "Well... when does this expression equal 0. In other words, lets solve:
\n" ); document.write( "\"%286x%2B2%29%5E2-4%286x%2B2%29=0\"
\n" ); document.write( "Again, we can expand this, or we could see that each term has a common factor of (6x+2) and factor this out. This leaves:
\n" ); document.write( "\"%286x%2B2%29%28%286x%2B2%29-4%29=0\"
\n" ); document.write( "\"%286x%2B2%29%286x-2%29=0\"\r
\n" ); document.write( "\n" ); document.write( "If two things multiply to give a product of 0, then at least one of them must be 0. This means
\n" ); document.write( "\"%286x%2B2%29=0\"
\n" ); document.write( "\"6x=-2\"
\n" ); document.write( "\"x=-1%2F3\"
\n" ); document.write( "or
\n" ); document.write( "\"%286x-2%29=0\"
\n" ); document.write( "\"6x=2\"
\n" ); document.write( "\"x=1%2F3\"\r
\n" ); document.write( "\n" ); document.write( "This means x can be anything except \"1%2F3\" and \"-1%2F3\".\r
\n" ); document.write( "\n" ); document.write( "Hopefully this helps! Please let me know if you still do not understand:)
\n" ); document.write( "
\n" );