document.write( "Question 547274: $\"2p%5E%282%29-119=3p\"$ \n" ); document.write( "

Algebra.Com's Answer #356322 by mathie123(224) $\"\"$ $\"About$

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$\"2p%5E%282%29-119=3p\"$ \r
\n" ); document.write( "\n" ); document.write( "Since we have a $\"p%5E2\"$ term (and this is the biggest term), a $\"p\"$ term and a constant, it is a quadratic. We can put it into $\"ax%5E2%2Bbx%2Bc=0\"$ form. \r
\n" ); document.write( "\n" ); document.write( " $\"2p%5E%282%29-3p-119=0\"$ \r
\n" ); document.write( "\n" ); document.write( "We could try to think of two numbers that multiply to $\"2%2A-119\"$ and add to $\"-3\"$ . But this may be hard to think of. Instead we will use the quadratic formula which states (I will use p instead of x, though x is most commonly used):
\n" ); document.write( " $\"p=%28-%28b%29%2B+sqrt%28%28b%29%5E2-4%28a%29%28c%29%29%29%2F2%28a%29\"$
\n" ); document.write( "or
\n" ); document.write( " $\"p=%28-%28b%29-+sqrt%28%28b%29%5E2-4%28a%29%28c%29%29%29%2F2%28a%29\"$ \r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " $\"p=%28-%28-3%29%2B+sqrt%28%28-3%29%5E2-4%282%29%28-119%29%29%29%2F2%282%29\"$
\n" ); document.write( " $\"p=%283%2B+sqrt%289%2B952%29%29%2F4\"$
\n" ); document.write( " $\"p=%283%2B+sqrt%28961%29%29%2F4\"$
\n" ); document.write( " $\"p=%283%2B+31%29%2F4\"$
\n" ); document.write( " $\"p=%283%2B31%29%2F4\"$
\n" ); document.write( " $\"p=34%2F4\"$
\n" ); document.write( " $\"p=8.5\"$
\n" ); document.write( "OR
\n" ); document.write( " $\"p=%28-%28-3%29-+sqrt%28%28-3%29%5E2-4%282%29%28-119%29%29%29%2F2%282%29\"$
\n" ); document.write( " $\"p=%283-+sqrt%289%2B952%29%29%2F4\"$
\n" ); document.write( " $\"p=%283-+sqrt%28961%29%29%2F4\"$
\n" ); document.write( " $\"p=%283-+31%29%2F4\"$
\n" ); document.write( " $\"p=%283-31%29%2F4\"$
\n" ); document.write( " $\"p=-28%2F4\"$
\n" ); document.write( " $\"p=-7\"$
\n" ); document.write( " \n" ); document.write( "

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