document.write( "Question 547239: Solve by the elimination method.
\n" ); document.write( "7r-3s=3
\n" ); document.write( "3r+7s=51
\n" ); document.write( "I think there is no solution but I'm not sure if I'm correct.
\n" ); document.write( "

Algebra.Com's Answer #356312 by mathie123(224)\"\" \"About 
You can put this solution on YOUR website!
There are a few ways to do this, depending on what variable you want to eliminate. Just to make it simple, I will eliminate my r.
\n" ); document.write( "\"7r-3s=3\" (1)
\n" ); document.write( "\"3r%2B7s=51\" (2)\r
\n" ); document.write( "\n" ); document.write( "I will multiply my equation (1) by 3 (the number in front of r in equation (2)), and my equation (2) by 7 (you guessed it.... the number in front of r in equation (1)). This leaves:
\n" ); document.write( "\"21r-9s=9\" (3)
\n" ); document.write( "\"21r%2B49s=357\" (4)\r
\n" ); document.write( "\n" ); document.write( "Now Subtracting equation (4) by equation (3) we get:
\n" ); document.write( "\"%2821r-9s%29-%2821r%2B49s%29=9-357\"
\n" ); document.write( "\"-9s-49s=-348\"
\n" ); document.write( "\"-58s=-348\"
\n" ); document.write( "\"-58s%2F-58=-348%2F-58\"
\n" ); document.write( "\"s=6\"\r
\n" ); document.write( "\n" ); document.write( "Now we can substitute this value of s into any of the equations (1)-(4). I will put it into equation (1).
\n" ); document.write( "\"7r-3%2A6=3\"
\n" ); document.write( "\"7r-18=3\"
\n" ); document.write( "\"7r-18%2B18=3%2B18\"
\n" ); document.write( "\"7r=21\"
\n" ); document.write( "\"7r%2F7=21%2F7\"
\n" ); document.write( "\"r=3\"
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