document.write( "Question 547152: The center of a circle is (4, 6), and an endpoint of a diameter is (2, 5). What is the other endpoint of the diameter? \n" ); document.write( "

Algebra.Com's Answer #356304 by KMST(5328) $\"\"$ $\"About$

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If the center of the circle is at (4,6), the diameter that has one end at (2,5) must have the other end at (6,7).
\n" ); document.write( "The other end must be at the same distance and on the same line.
\n" ); document.write( "Let's call the point we are looking for (x,y).
\n" ); document.write( "You could say that the center of the circle is the midpoint of that diameter and so
\n" ); document.write( " $\"4=%28x%2B2%29%2F2\"$ and $\"6=%28y%2B5%29%2F2\"$ and solve those equations for $\"x\"$ and for $\"y\"$
\n" ); document.write( "In my head, I just figured that if going from (2,5) to center (4,6) I had to add 2 to the x-coordinate and 1 to the y-coordinate, doing the same again would get me to the other end of the diameter, so I added $\"4%2B2=6\"$ and $\"6%2B1=7\"$ in my head. It would have worked well for speed, if there was no show-your-work rule.
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