document.write( "Question 547000: a train leaves Slaton traveling east at 80 km/h. an hour later anothertrain leaves Slaton on a parallel track at 120 km/h. how far from Slaton will the trains meet?
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Algebra.Com's Answer #356287 by ankor@dixie-net.com(22740)\"\" \"About 
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a train leaves Slaton traveling east at 80 km/h.
\n" ); document.write( " an hour later another train leaves Slaton on a parallel track at 120 km/h.
\n" ); document.write( "how far from Slaton will the trains meet?
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\n" ); document.write( "First find the time it takes them to meet
\n" ); document.write( "Let t = travel time of the 1st train
\n" ); document.write( "then
\n" ); document.write( "(t-1) = travel time of the 2nd train
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\n" ); document.write( "When they meet, they will have traveled the same distance,
\n" ); document.write( "Write a distance equation, dist = speed * time
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\n" ); document.write( "120(t-) = 80t
\n" ); document.write( "120t - 120 = 80t
\n" ); document.write( "120t - 80t = 120
\n" ); document.write( "40t = 120
\n" ); document.write( "t = 3 hrs
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\n" ); document.write( "Find the distance with the 1st train: 80*3 = 240 km from Slayton
\n" ); document.write( "Check the distance with the 2nd train: 120*2 = 240 km\r
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