document.write( "Question 547158: what is the answer for the equation f(x)=x^4-6x^3+11x^2+12x-26 divided by 3-2i \n" ); document.write( "
| Algebra.Com's Answer #356265 by Edwin McCravy(20064)     You can put this solution on YOUR website! \r\n" ); document.write( "f(x)=x^4-6x^3+11x^2+12x-26 divided by 3-2i\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " 3-2i | 1 -6 11 12 -26\r\n" ); document.write( " |____________________________\r\n" ); document.write( "\r\n" ); document.write( "Bring down the 1\r\n" ); document.write( "\r\n" ); document.write( " 3-2i | 1 -6 11 12 -26\r\n" ); document.write( " | \r\n" ); document.write( " 1\r\n" ); document.write( "\r\n" ); document.write( "Multiply the 1 by the 3-2i: 1(3-2i) = 3-2i. Write that under the -6\r\n" ); document.write( "like this:\r\n" ); document.write( "\r\n" ); document.write( " 3-2i | 1 -6 11 12 -26\r\n" ); document.write( " | 3-2i \r\n" ); document.write( " 1\r\n" ); document.write( " \r\n" ); document.write( "Add -6 and 3-2i, getting -3-2i. Put that underneath the line to\r\n" ); document.write( "the right of the 1, like this:\r\n" ); document.write( "\r\n" ); document.write( " 3-2i | 1 -6 11 12 -26\r\n" ); document.write( " | 3-2i \r\n" ); document.write( " 1 -3-2i\r\n" ); document.write( "\r\n" ); document.write( "Multiply the -3-2i by the 3-2i: (-3-2i)(3-2i) = -9+6i-6i+4i² \r\n" ); document.write( "= -9+4(-1) = -9-4 = -13. Write than under the 11 like this:\r\n" ); document.write( "\r\n" ); document.write( " 3-2i | 1 -6 11 12 -26\r\n" ); document.write( " | 3-2i -13 \r\n" ); document.write( " 1 -3-2i\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Add 11 and -13, getting -2. Put that underneath the line to\r\n" ); document.write( "the right of the -3-2i, like this:\r\n" ); document.write( "\r\n" ); document.write( " 3-2i | 1 -6 11 12 -26\r\n" ); document.write( " | 3-2i -13 \r\n" ); document.write( " 1 -3-2i -2\r\n" ); document.write( "\r\n" ); document.write( "Multiply the -2 by the 3-2i: -2(3-2i) =-6+4i. Write that under the 12\r\n" ); document.write( "like this:\r\n" ); document.write( "\r\n" ); document.write( " 3-2i | 1 -6 11 12 -26\r\n" ); document.write( " | 3-2i -13 -6+4i \r\n" ); document.write( " 1 -3-2i -2 6+4i\r\n" ); document.write( "\r\n" ); document.write( "Multiply the 6+4i by the 3-2i: (6+4i)(3-2i) = 18-12i+12i-8i² \r\n" ); document.write( "= 18-8(-1) = 18+8 = 26. Write than under the -26 like this:\r\n" ); document.write( "\r\n" ); document.write( " 3-2i | 1 -6 11 12 -26\r\n" ); document.write( " | 3-2i -13 -6+4i 26\r\n" ); document.write( " 1 -3-2i -2 6+4i\r\n" ); document.write( "\r\n" ); document.write( "Add and get 0 remainder\r\n" ); document.write( "\r\n" ); document.write( " 3-2i | 1 -6 11 12 -26\r\n" ); document.write( " | 3-2i -13 -6+4i 26\r\n" ); document.write( " 1 -3-2i -2 6+4i 0\r\n" ); document.write( "\r\n" ); document.write( "We interpret that bottom line as coefficients of a\r\n" ); document.write( "polynomial of one less degree than the original. The\r\n" ); document.write( "degree of the original is 4, so this will be of degree 3:\r\n" ); document.write( "\r\n" ); document.write( " x³ + (-3-2i)x² - 2x + (6+4i)\r\n" ); document.write( "\r\n" ); document.write( "That's the answer. or you can factor out a negative\r\n" ); document.write( "from the second coefficiens:\r\n" ); document.write( "\r\n" ); document.write( " x³ - (3+2i)x² - 2x + (6+4i)\r\n" ); document.write( "\r\n" ); document.write( "Edwin\n" ); document.write( " |