document.write( "Question 53363This question is from textbook
\n" ); document.write( ": A bus traveled at an average rate of 50 miles per hour and then reduced its average rate to 40 miler per hour for the rest of the trip. If the 220-mile trip took 5 hours, determine how long the bus traveled at each rate. \n" ); document.write( "
Algebra.Com's Answer #35623 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
A bus traveled at an average rate of 50 miles per hour and then reduced its average rate to 40 miler per hour for the rest of the trip. If the 220-mile trip took 5 hours, determine how long the bus traveled at each rate.
\n" ); document.write( "-------------
\n" ); document.write( "50 mph DATA:
\n" ); document.write( "distance = x miles ; rate=50 mph; time=d/r = x/50\r
\n" ); document.write( "\n" ); document.write( "40 mph DATA:
\n" ); document.write( "distance = 220-x ; rate= 40 mph; time = d/r = (220-x)/40\r
\n" ); document.write( "\n" ); document.write( "EQUATION:
\n" ); document.write( "time + time = 5 hrs.
\n" ); document.write( "x/50 + (220-x)/40 = 5
\n" ); document.write( "Multiply thru by 200 to get:
\n" ); document.write( "4x + 5(220-x)= 1000
\n" ); document.write( "4x + 1100-5x= 1000
\n" ); document.write( "-x= -100
\n" ); document.write( "x=100 miles at 50 mph
\n" ); document.write( "220-100= 120 miles at 40 mph
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( " \n" ); document.write( "
\n" );