document.write( "Question 546850: the perimeter of a pentagon (4x +4) is three times the perimeter of a triangle (x + 3) find x. also calculate perimeters of both and a regular octagon has the same perimeter what is lenth of each side? i dont understand this. i tried 3(4x+4) an got 12x + 12 am i on theright track? \n" ); document.write( "
Algebra.Com's Answer #356226 by boilpoil(127)\"\" \"About 
You can put this solution on YOUR website!
No, you are on the wrong track. Perimeter of pentagon (4x+4) is(=) 3 times(3(?)) the perimeter of a triangle(3(x+3)).\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So, according to the previous analysis:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "4x+4=3(x+3)
\n" ); document.write( "4x+4=3x+9
\n" ); document.write( "x=5\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Perimeter of pentagon
\n" ); document.write( "=4(5)+4
\n" ); document.write( "=20+4
\n" ); document.write( "=24\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Perimeter of triangle
\n" ); document.write( "=5+3
\n" ); document.write( "=8\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "If the perimeter of the octagon equals the perimeter of pentagon(P) OR triangle(T)
\n" ); document.write( "P=24÷8
\n" ); document.write( "=3\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "T=8÷8
\n" ); document.write( "=1\r
\n" ); document.write( "\n" ); document.write( "***Does not know the what the perimeter of the octagon equals so I do both for you***
\n" ); document.write( " \n" ); document.write( "
\n" );