document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=53368>Question 53368</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/9780073268620/algebrahomeworkh>University of phoenix elementary and intermediate algebra</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> THE BASAL ENERGY REQUIREMENT B IS THE NUMBER OF CALORIES THAT A PERSON NEEDS TO MAINTIAN THE LIFE PROCESS.  FOR A 28 YEAR OLD FEMALE WITH THE HEIGHT OF 160CENTIMETERS AND A WEIGHT OF 45 KILOGRAMS (KG), B IS 1300 CALIROIES.  IF HER WEIGHT INCREASED TO 50 KILOGRAMS, THEN B IS 1365 CALORIES. THERE IS A LINEAR EQUATION THAT EXPRESS B IN TERMS OF HER WEIGHT W. FIND THE EQUATION AND FIND THE BASAL ENERGY REQUIREMENT IF HER WEIGHT IS 53.2 KILOGRAMS.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #35621 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=35621\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You have two points, (45,1300) and (50,1365)<BR>\n" );
document.write( "Slope = [1365-1300]/[50-45]= 65/5= 13<BR>\n" );
document.write( "1300=13(45)+b<BR>\n" );
document.write( "b= 715<BR>\n" );
document.write( "EQUATION:<BR>\n" );
document.write( "B= 13(weight)+715<BR>\n" );
document.write( "B(53.2)= 13(53.2)+715<BR>\n" );
document.write( "B(53.2)= 1406 calories if she weighs 53.2 kg.<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );