document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=547085>Question 547085</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Chemistry. E-Chem Testing has a solution that is 80% base and another that is 30% base. A technician needs 150 L of a solution that is 62% base. The 150 L will be prepared by mixing the two solutions on hand. How much of each should be used? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #356205 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=356205\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> percent		----------------			quantity								<BR>\n" );
document.write( "Base I	80	----------------			x	L							<BR>\n" );
document.write( "Base II	30	------	150	-	x	L							<BR>\n" );
document.write( "Mixture	62.00%	----------------	150										<BR>\n" );
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document.write( "80x+30(150-x)=62*150	<BR>\n" );
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document.write( "80x+4500-30x=9300			<BR>\n" );
document.write( "80x-30x	=9300-4500			<BR>\n" );
document.write( "50x=4800								<BR>\n" );
document.write( "/	50												<BR>\n" );
document.write( "x	=96L	80.00%		Base I	<BR>\n" );
document.write( "54L             30.00%		Base II	<BR>\n" );
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document.write( "m.ananth@hotmail.ca													<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );