document.write( "Question 547071: Solve using two equations in two variables.\r
\n" );
document.write( "\n" );
document.write( "Kathleen invested $5000, some at 6% and the rest at 5%. Her annual income from the investments is $280. How much is invested at 5%? \n" );
document.write( "
Algebra.Com's Answer #356190 by mananth(16946) You can put this solution on YOUR website! Fund A 5.00% per annum ---x \n" ); document.write( "Fund B 6.00% per annum ---y \n" ); document.write( " \n" ); document.write( "x+y=5000 ------------------------1 \n" ); document.write( "5.00% x + 6.00% y= = $280.00 \n" ); document.write( "Multiply by 100 \n" ); document.write( "5x+6y= $28,000.00 --------2 \n" ); document.write( " \n" ); document.write( "Multiply (1) by -5 \n" ); document.write( "we get \n" ); document.write( " \n" ); document.write( "-5x-5y= -25000.00 \n" ); document.write( " \n" ); document.write( "Add this to (2) \n" ); document.write( " \n" ); document.write( "y =$3,000.00 investment at 6.00% \n" ); document.write( "Balance $2,000.00 investment at 5.00% \n" ); document.write( "CHECK \n" ); document.write( "$2,000.00 --------- 5.00% ------- $100.00 \n" ); document.write( "$3,000.00 ------- 6.00% ------- $180.00 \n" ); document.write( "Total -------------- $280.00 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |