document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=546938>Question 546938</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find three consecutive odd numbers such that three times the smallest number is the same as nine more than twice the largest. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #356145 by </B><A HREF=/tutors/aboutme.mpl?userid=Maths68><B>Maths68(1474)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Maths68><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Maths68><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=356145\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let <BR>\n" );
document.write( "First odd integer = x+1<BR>\n" );
document.write( "Second odd integer = x+3<BR>\n" );
document.write( "Third odd integer = x+5<BR>\n" );
document.write( "Given<BR>\n" );
document.write( "Three times the smallest number is the same as nine more than twice the largest<BR>\n" );
document.write( "3(x+1)=2(x+5)+9<BR>\n" );
document.write( "3x+3=2x+10+9<BR>\n" );
document.write( "3x+3=2x+10+9<BR>\n" );
document.write( "3x-2x=19-3<BR>\n" );
document.write( "x=16\r<BR>\n" );
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document.write( "First odd integer = x+1 = 16+1=17<BR>\n" );
document.write( "Second odd integer = x+3=16+3=19<BR>\n" );
document.write( "Third odd integer = x+5=16+5=21\r<BR>\n" );
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document.write( " </SPAN>\n" );
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