document.write( "Question 546864: Find the slope and y-intercept of the line that is perpendicular to y=1/3x-3 and passes through the point (-4, 3).
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Algebra.Com's Answer #356130 by mananth(16946)\"\" \"About 
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y = 1/ 3 x + -3
\n" ); document.write( "Compare this equation with y=mx+b, m= slope & b= y intercept
\n" ); document.write( "slope m = 1/3
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\n" ); document.write( "The slope of a line perpendicular to the above line will be the negative reciprocal -3
\n" ); document.write( "m1*m2=-1
\n" ); document.write( "The slope of the required line will be -3
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\n" ); document.write( "m= -3 ,point ( -4 , 3 )
\n" ); document.write( "Find b by plugging the values of m & the point in
\n" ); document.write( "y=mx+b
\n" ); document.write( "3 = 12.00 + b
\n" ); document.write( "b= -9
\n" ); document.write( "m= -3
\n" ); document.write( "The required equation is y =-3x-9
\n" ); document.write( "m.ananth@hotmail.ca
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