document.write( "Question 546910: The number \"N\" is a 5 digit natural number. The 6 digit number N1, formed by placing the digit 1 after N, is 3 times as large as the 6 digit number 1N, formed by placing the 1 in front of N. What is the original 5 digit number N? Write each as an algebraic expression: N1 = ? and 1N = ? Write the equation to solve for finding \"N\"= \n" ); document.write( "

Algebra.Com's Answer #356122 by AnlytcPhil(1806) $\"\"$ $\"About$

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The number \"N\" is a 5 digit natural number. The 6 digit number N1, formed by placing the digit 1 after N, is 3 times as large as the 6 digit number 1N, formed by placing the 1 in front of N. What is the original 5 digit number N? Write each as an algebraic expression: N1 = ? and 1N = ? Write the equation to solve for finding \"N\"=
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document.write( " N = ↏↏↏↏↏\r\n" );
document.write( "N1 = ↏↏↏↏↏1 = 10N + 1\r\n" );
document.write( "1N = 1↏↏↏↏↏ = 100000 + N\r\n" );
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document.write( "10N + 1 = 3(100000 + N)\r\n" );
document.write( "10N + 1 = 300000 + 3N\r\n" );
document.write( "     7N = 299999\r\n" );
document.write( "      N =  42857\r\n" );
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document.write( "     N1 = 428571\r\n" );
document.write( "     1N = 142857\r\n" );
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document.write( "Edwin

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