document.write( "Question 546819: A rectange shed covers 300 feet of ground. It is 6 feet longer than it is wide. What is the width of the shed to the nearest tenth of a foot?\r
\n" ); document.write( "\n" ); document.write( "This is what I tried:
\n" ); document.write( "x = width
\n" ); document.write( "x + 6 = length
\n" ); document.write( "Area of a Rectangle = 300 \r
\n" ); document.write( "\n" ); document.write( "What I set up: 300 = x(x + 6)
\n" ); document.write( "Which then I got: 300 = x^2 +6x\r
\n" ); document.write( "\n" ); document.write( "That is all I could figure out.
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Algebra.Com's Answer #356094 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
What you've done so far is good!
\n" ); document.write( "Now you need to solve the resulting quadratic equation for x (the width).
\n" ); document.write( "\"x%5E2%2B6x-300+=+0\" Use the quadratic formula: \"x+=+%28b%2B-sqrt%28b%5E2-4ac%29%29%2F2a\" where: a = 1, b = 6, and c = -300.
\n" ); document.write( "\"x+=+9-6%2B-sqrt%286%5E2-4%281%29%28-300%29%29%2F2%281%29\" which evaluates to:
\n" ); document.write( "\"x+=+-20.578\"or \"x+=+14.578\" Discard the negative solution as the width (x) must be a positive value.
\n" ); document.write( "\"x+=+14.6\"
\n" ); document.write( "The width is 14.6 feet (to the nearest tenth of a foot).
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