document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=546665>Question 546665</A>: <I><SPAN STYLE=\"word-break: break-all;\"> State the reference angel associated with each rotation, then find the associated point (x,y) on the unit circle. Express non-integer values in the answer as reduced fractions, if necessary.\r<BR>\n" );
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document.write( "theta = 5pi/3\r<BR>\n" );
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document.write( "5pi/3 is in which quadrant?<BR>\n" );
document.write( "so the point is ? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #356073 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=356073\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2pi is a full circle ___ 2 = 6/3 ___ so 5pi/3 is 5/6 of a circle or 300º ___ quadrant IV ___ this is a 60º reference angle\r<BR>\n" );
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document.write( "x = cos(-60º) ___ y = sin(-60º) </SPAN>\n" );
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