document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=546661>Question 546661</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Using the approximate values: log(underscore 5) (6)= 1.1 and log(underscore 5) (10) = 1.4, find: Log(underscore 5) (1000). Also, log(underscore 5) (5) = 1.\r<BR>\n" );
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document.write( "Example: Using those values, find log(underscore 5) (30). The answer would be log(underscore 5) (5 * 6) which is log(underscore 5) (5) plus log(underscore 5) 6 which is 1 + 1.1 which equals 2.1\r<BR>\n" );
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document.write( "I dont know how to get 1000 out of those values. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #356071 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=356071\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 10*10*10 = 1000 </SPAN>\n" );
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