document.write( "Question 546553: The sum of Marian's age and David's age when they were married was 44. Five years after they were married, twice David's age minus three times Marian's age was -22. How old were each when they were married?\r
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\n" ); document.write( "\n" ); document.write( "I have tried using the elimination method by using two equations, but I'm still not sure. Please help me with this.
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Algebra.Com's Answer #356050 by mananth(16946)\"\" \"About 
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when they married \r
\n" ); document.write( "\n" ); document.write( "Marian's age = x
\n" ); document.write( "David's age =y\r
\n" ); document.write( "\n" ); document.write( "x+y=44\r
\n" ); document.write( "\n" ); document.write( "After 5 years
\n" ); document.write( "Marian's age = x+5
\n" ); document.write( "David's age = y+5\r
\n" ); document.write( "\n" ); document.write( "2(y+5)-3(x+5)=-22
\n" ); document.write( "2y+10-3x-15=-22
\n" ); document.write( "2y-3x=-17\r
\n" ); document.write( "\n" ); document.write( "1 x + 1 y = 44 .............1
\n" ); document.write( "-3 x + 2 y = -14 .............2
\n" ); document.write( "Eliminate y
\n" ); document.write( "multiply (1)by -2
\n" ); document.write( "Multiply (2) by 1
\n" ); document.write( "-2 x -2 y = -88
\n" ); document.write( "-3 x + 2 y = -14
\n" ); document.write( "Add the two equations
\n" ); document.write( "-5 x = -102.000
\n" ); document.write( "/ -5
\n" ); document.write( "x = 20 2/ 5 Marian's age
\n" ); document.write( "plug value of x in (1)
\n" ); document.write( "1 x + 1 y = 44
\n" ); document.write( "20.4 + 1 y = 44
\n" ); document.write( " 1 y = 44 -20.4
\n" ); document.write( " 1 y = 23.6
\n" ); document.write( " y = 23 3/ 5 David's age
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