document.write( "Question 546553: The sum of Marian's age and David's age when they were married was 44. Five years after they were married, twice David's age minus three times Marian's age was -22. How old were each when they were married?\r
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document.write( "I have tried using the elimination method by using two equations, but I'm still not sure. Please help me with this. \n" );
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Algebra.Com's Answer #356050 by mananth(16946)![]() ![]() You can put this solution on YOUR website! when they married \r \n" ); document.write( "\n" ); document.write( "Marian's age = x \n" ); document.write( "David's age =y\r \n" ); document.write( "\n" ); document.write( "x+y=44\r \n" ); document.write( "\n" ); document.write( "After 5 years \n" ); document.write( "Marian's age = x+5 \n" ); document.write( "David's age = y+5\r \n" ); document.write( "\n" ); document.write( "2(y+5)-3(x+5)=-22 \n" ); document.write( "2y+10-3x-15=-22 \n" ); document.write( "2y-3x=-17\r \n" ); document.write( "\n" ); document.write( "1 x + 1 y = 44 .............1 \n" ); document.write( "-3 x + 2 y = -14 .............2 \n" ); document.write( "Eliminate y \n" ); document.write( "multiply (1)by -2 \n" ); document.write( "Multiply (2) by 1 \n" ); document.write( "-2 x -2 y = -88 \n" ); document.write( "-3 x + 2 y = -14 \n" ); document.write( "Add the two equations \n" ); document.write( "-5 x = -102.000 \n" ); document.write( "/ -5 \n" ); document.write( "x = 20 2/ 5 Marian's age \n" ); document.write( "plug value of x in (1) \n" ); document.write( "1 x + 1 y = 44 \n" ); document.write( "20.4 + 1 y = 44 \n" ); document.write( " 1 y = 44 -20.4 \n" ); document.write( " 1 y = 23.6 \n" ); document.write( " y = 23 3/ 5 David's age \n" ); document.write( " \n" ); document.write( " |