document.write( "Question 546536: Please help me solve this \r
\n" ); document.write( "\n" ); document.write( "The sum of the present ages of two sisters Ling and Mei is 44 years.4 years ago Ling was thrice as old as Mei .Find their present ages.
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Algebra.Com's Answer #356037 by mananth(16946)\"\" \"About 
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Ling x years
\n" ); document.write( "Mei --- y years\r
\n" ); document.write( "\n" ); document.write( "x+y=44...................(1)\r
\n" ); document.write( "\n" ); document.write( "4 years ago
\n" ); document.write( "ling = x-4
\n" ); document.write( "Mei = y-4\r
\n" ); document.write( "\n" ); document.write( "(x-4)=3(y-4)
\n" ); document.write( "x-4 = 3y-12
\n" ); document.write( "x-3y=-8...................(2)\r
\n" ); document.write( "\n" ); document.write( "Multiply (1) by 3
\n" ); document.write( "3x+3y=132\r
\n" ); document.write( "\n" ); document.write( "add it to (2)
\n" ); document.write( "4x=124
\n" ); document.write( "/4
\n" ); document.write( "x=31 lings age
\n" ); document.write( "Mei's age = 44-31=13
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