document.write( "Question 546534: Please help me solve this \r
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document.write( "Kelvin,John and Samy had $374.Kelvin had thrice as much as Samy and twice as much as John .How much did Kelvin have ?\r
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document.write( "Thank you \n" );
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Algebra.Com's Answer #356034 by mananth(16946) You can put this solution on YOUR website! Let kelvin have x\r \n" ); document.write( "\n" ); document.write( "Samy has 1/3 x\r \n" ); document.write( "\n" ); document.write( "John has 1/2 x\r \n" ); document.write( "\n" ); document.write( "x+x/3+x/2=374 \n" ); document.write( "LCD =6 multiply by 6 \n" ); document.write( "6x+2x+3x=2244 \n" ); document.write( "11x=2244 \n" ); document.write( "/11 \n" ); document.write( "x=204 \n" ); document.write( "Kelvin had $204\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |