document.write( "Question 543706: Need help solving logarithm\r
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document.write( "log(x^2+4)-log(x+2)=2+log(x-2) \n" );
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Algebra.Com's Answer #355990 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! log(x^2+4)-log(x+2)=2+log(x-2) \n" ); document.write( "log(x^2+4)-log(x+2)-log(x-2)=2 \n" ); document.write( "log(x^2+4)-(log(x+2)+log(x-2))=2 \n" ); document.write( "place under single log \n" ); document.write( "log{[(x^2+4)]/[(x+2)(x-2)]}=2 \n" ); document.write( "log{[(x^2+4)]/[(x^2-4]}=2 \n" ); document.write( "convert to exponential form: base(10) raised to log of number(2)=number[(x^2+4)]/[(x^2-4] \n" ); document.write( "10^2=(x^2+4)/(x^2-4)=100 \n" ); document.write( "100x^2-400=x^2+4 \n" ); document.write( "99x^2=404 \n" ); document.write( "x^2=404/99≈4.08 \n" ); document.write( "x≈2.02 \n" ); document.write( " |