document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=546452>Question 546452</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I'm having trouble with a word problem. It states: The current in a stream is 2mph. Find the speed of the boat in still water if it goes 26 miles downstream in the same amount of time it takes to go 18 miles upstream. I know I should use d=rt, but I don't know how. Thanks! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #355988 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=355988\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Boat speed		x	mph				<BR>\n" );
document.write( "current speed 		2	mph				<BR>\n" );
document.write( "..							<BR>\n" );
document.write( "against wind   		x	-	2	mph		<BR>\n" );
document.write( "with wind  		x   	+	2	mph		<BR>\n" );
document.write( "							<BR>\n" );
document.write( "Distance against 	current	18					<BR>\n" );
document.write( "Distance with 	current	26					<BR>\n" );
document.write( "Time = same	equate the time against to time with current						<BR>\n" );
document.write( "t=d/r							<BR>\n" );
document.write( "18	/(x-	2	)=	26	/(x+	2	)<BR>\n" );
document.write( "18	*(x+	2	)=	26	*(x-	2	)<BR>\n" );
document.write( "18	x  	+	36	=	26	x	-52<BR>\n" );
document.write( "26	x  	-18	x   	=	52	+	36<BR>\n" );
document.write( "8	x  	=	88				<BR>\n" );
document.write( "/	8						<BR>\n" );
document.write( "	x=	11	mph				<BR>\n" );
document.write( "m.ananth@hotmail.ca							<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );