document.write( "Question 545749: log(6x+5)=1+log(x-8) \n" ); document.write( "

Algebra.Com's Answer #355978 by lwsshak3(11628) $\"\"$ $\"About$

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log(6x+5)=1+log(x-8)
\n" ); document.write( "log(6x+5)-log(x-8)=1
\n" ); document.write( "log[(6x+5)/(x-8)]=1
\n" ); document.write( "exponential form: base(10) raised to log of number(1)=number[(6x+5)/(x-8)]
\n" ); document.write( "10^1=(6x+5)/(x-8)=10
\n" ); document.write( "6x+5=10x-80
\n" ); document.write( "4x=85
\n" ); document.write( "x=21.25 \n" ); document.write( "

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