document.write( "Question 546447: log(x-9)=1-logx
\n" ); document.write( "i do not just want the answer, i want steps on how to do it so i can apply it to my test \n" ); document.write( "

Algebra.Com's Answer #355975 by lwsshak3(11628) $\"\"$ $\"About$

You can put this solution on YOUR website!
log(x-9)=1-logx
\n" ); document.write( "log(x-9)+logx=1
\n" ); document.write( "adddition in logs indicates multiplication in operations
\n" ); document.write( "log[(x-9)*x]=1
\n" ); document.write( "convert to exponential form: base(10) raised to log of number(1)=number[(x-9)*x]
\n" ); document.write( "10^1=[(x-9)*x]
\n" ); document.write( "x^2-9x-10=0
\n" ); document.write( "(x-10)(x+1)=0
\n" ); document.write( "x=-1 (reject, x>0)
\n" ); document.write( "or
\n" ); document.write( "x=10 (ans) \n" ); document.write( "

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