document.write( "Question 546420: Write the equation in standard form of the line that is perpendicular to the line y=-2x+6 and passes through the point (-4,8) \n" ); document.write( "

Algebra.Com's Answer #355972 by mananth(16946) $\"\"$ $\"About$

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1 y = -2 x + 6
\n" ); document.write( "Divide by 1
\n" ); document.write( " y = -2 x + 6
\n" ); document.write( "Compare this equation with y=mx+b, m= slope & b= y intercept
\n" ); document.write( "slope m = -2
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\n" ); document.write( "The slope of a line perpendicular to the above line will be the negative reciprocal 0.5
\n" ); document.write( "m1*m2=-1
\n" ); document.write( "The slope of the required line will be 1/2
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\n" ); document.write( "m= 1/2 ,point ( -4 , 8 )
\n" ); document.write( "Find b by plugging the values of m & the point in
\n" ); document.write( "y=mx+b
\n" ); document.write( "8 = -2.00 + b
\n" ); document.write( "b= 10
\n" ); document.write( "m= 1/2
\n" ); document.write( "The required equation is , y = 1/ 2 x + 10
\n" ); document.write( "multiply by 2
\n" ); document.write( "2y=x+20
\n" ); document.write( "-x+2y=20
\n" ); document.write( "m.ananth@hotmail.ca
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