document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=546395>Question 546395</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A chemist wants to make 40 liters of 22.5% acid solution.  She is going to make it by mixing a 10% acid and a 30% acid solution.  How many liters of each will she need? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #355962 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=355962\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A chemist wants to make 40 liters of 22.5% acid solution. She is going to make it by mixing a 10% acid and a 30% acid solution. How many liters of each will she need?<BR>\n" );
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document.write( "Let x = amount (liters) of 10% acid<BR>\n" );
document.write( "then<BR>\n" );
document.write( "40-x = amount (liters) of 30% acid<BR>\n" );
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document.write( ".10x + .30(40-x) = .225(40)<BR>\n" );
document.write( ".10x + 12-.30x = 9<BR>\n" );
document.write( "12-.20x = 9<BR>\n" );
document.write( "12 = 9+.20x<BR>\n" );
document.write( "3 = .20x<BR>\n" );
document.write( "3/.20 = x<BR>\n" );
document.write( "15 liters = x (amount of 10% acid)<BR>\n" );
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document.write( "Amount of 30% acid:<BR>\n" );
document.write( "40-x = 40-15 = 25 liters\r<BR>\n" );
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