document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=546404>Question 546404</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The second angle of a triangle is two times as large as the first. The third angle is 15 degrees less than the sum of the other two angles. What is the measure of the first angle? please show all steps </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #355959 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16949)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=355959\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> first angle = x<BR>\n" );
document.write( "second angle = 2x<BR>\n" );
document.write( "Third angle =x+2x-15==>3x-15\r<BR>\n" );
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document.write( "Sum of all angles of triangle = 180 deg\r<BR>\n" );
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document.write( "x+2x+3x-15=180\r<BR>\n" );
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document.write( "6x-15=180<BR>\n" );
document.write( "6x=180+15<BR>\n" );
document.write( "6x=195<BR>\n" );
document.write( "x=195/6<BR>\n" );
document.write( "x=32.5 deg\r<BR>\n" );
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document.write( "second angle = 2x==> 65 deg\r<BR>\n" );
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document.write( "Third angle = 3x-15==> 3*32.5-15<BR>\n" );
document.write( "=97.50-15<BR>\n" );
document.write( "=82.5 deg<BR>\n" );
document.write( "82.5+32.5+65=<BR>\n" );
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