document.write( "Question 53340This question is from textbook MEI structured mathematics A2 Pure mathematics c3/c4
\n" ); document.write( ": \"y=x%2A%289-2%2Ax%5E2%29%5E0.5\"
\n" ); document.write( " if y= 0
\n" ); document.write( "and x=a\r
\n" ); document.write( "\n" ); document.write( "Find the value of a giving your answer as a multiple of \"2%5Eo.5\"\r
\n" ); document.write( "\n" ); document.write( "the answer it gives is \"%283%2A2%5E0.5%29%2F2\"\r
\n" ); document.write( "\n" ); document.write( "i keep trying this problem but cant get anywhere near the answer it gives, and cant see where im going wrong. \r
\n" ); document.write( "\n" ); document.write( "i keep getting
\n" ); document.write( "\"2%5Eo.5%2F3\" or \"3%2F2%5E0.5\"\r
\n" ); document.write( "\n" ); document.write( "can you help?
\n" ); document.write( "

Algebra.Com's Answer #35595 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
\"y+=+x%289-2x%5E2%29%5E%280.5%29\" First, square both sides of the equation.
\n" ); document.write( "\"y%5E2+=+x%5E2%289-2x%5E2%29\" Now substitute y = 0 and x = a.
\n" ); document.write( "\"0+=+a%5E2%289-a%5E2%29\" Apply the zero product principle.
\n" ); document.write( "\"a%5E2+=+0\" and/or \"9-2a%5E2+=+0\"
\n" ); document.write( "\"9-2a%5E2+=+0\" Subtract 9 from both sides.
\n" ); document.write( "\"-2a%5E2+=+-9\" Divide both sides by -2.
\n" ); document.write( "\"a%5E2+=+9%2F2\" Take the square root of both sides.
\n" ); document.write( "\"a+=+3%2F%282%29%5E%280.5%29\" Finally, multiply numerator and denominator by \"2%5E%280.5%29\"
\n" ); document.write( "\"a+=+%283%2A2%5E%280.5%29%29%2F2\"
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