document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=545845>Question 545845</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How to solve for log16-2log2???? NEED HELP ! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #355922 by </B><A HREF=/tutors/aboutme.mpl?userid=NAMath><B>NAMath(12)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=NAMath><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=355922\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> In order two solve this you must first transfer anything in front of the logarithms to the exponents so...<BR>\n" );
document.write( "log16-log2^2<BR>\n" );
document.write( "log16-log4<BR>\n" );
document.write( "Now you must use a log rule that states when you subtract two logs you divide them so...<BR>\n" );
document.write( "log(16/4)<BR>\n" );
document.write( "log(4)<BR>\n" );
document.write( "Final Answer: .602059991 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );